Class Solution
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public final class Solution3042 - Count Prefix and Suffix Pairs I\.
Easy
You are given a 0-indexed string array
words.Let's define a boolean function
isPrefixAndSuffixthat takes two strings,str1andstr2:isPrefixAndSuffix(str1, str2)returnstrueifstr1is both a prefix and a suffix ofstr2, andfalseotherwise.
For example,
isPrefixAndSuffix("aba", "ababa")istruebecause"aba"is a prefix of"ababa"and also a suffix, butisPrefixAndSuffix("abc", "abcd")isfalse.Return an integer denoting the number of index pairs
(i, j)such thati < j, andisPrefixAndSuffix(words[i], words[j])istrue.Example 1:
Input: words = "a","aba","ababa","aa"
Output: 4
Explanation: In this example, the counted index pairs are:
i = 0 and j = 1 because isPrefixAndSuffix("a", "aba") is true.
i = 0 and j = 2 because isPrefixAndSuffix("a", "ababa") is true.
i = 0 and j = 3 because isPrefixAndSuffix("a", "aa") is true.
i = 1 and j = 2 because isPrefixAndSuffix("aba", "ababa") is true.
Therefore, the answer is 4.
Example 2:
Input: words = "pa","papa","ma","mama"
Output: 2
Explanation: In this example, the counted index pairs are:
i = 0 and j = 1 because isPrefixAndSuffix("pa", "papa") is true.
i = 2 and j = 3 because isPrefixAndSuffix("ma", "mama") is true.
Therefore, the answer is 2.
Example 3:
Input: words = "abab","ab"
Output: 0
Explanation: In this example, the only valid index pair is i = 0 and j = 1, and isPrefixAndSuffix("abab", "ab") is false.
Therefore, the answer is 0.
Constraints:
1 <= words.length <= 501 <= words[i].length <= 10words[i]consists only of lowercase English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegercountPrefixSuffixPairs(Array<String> words)-
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Method Detail
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countPrefixSuffixPairs
final Integer countPrefixSuffixPairs(Array<String> words)
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