Class Solution
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public final class Solution785 - Is Graph Bipartite?.
Medium
There is an undirected graph with
nnodes, where each node is numbered between0andn - 1. You are given a 2D arraygraph, wheregraph[u]is an array of nodes that nodeuis adjacent to. More formally, for eachvingraph[u], there is an undirected edge between nodeuand nodev. The graph has the following properties:There are no self-edges (
graph[u]does not containu).There are no parallel edges (
graph[u]does not contain duplicate values).If
vis ingraph[u], thenuis ingraph[v](the graph is undirected).The graph may not be connected, meaning there may be two nodes
uandvsuch that there is no path between them.
A graph is bipartite if the nodes can be partitioned into two independent sets
AandBsuch that every edge in the graph connects a node in setAand a node in setB.Return
trueif and only if it is bipartite.Example 1:
Input: graph = \[\[1,2,3],0,2,0,1,3,0,2]
Output: false
Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.
Example 2:
Input: graph = \[\[1,3],0,2,1,3,0,2]
Output: true
Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.
Constraints:
graph.length == n1 <= n <= 1000 <= graph[u].length < n0 <= graph[u][i] <= n - 1graph[u]does not containu.All the values of
graph[u]are unique.If
graph[u]containsv, thengraph[v]containsu.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final BooleanisBipartite(Array<IntArray> graph)-
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Method Detail
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isBipartite
final Boolean isBipartite(Array<IntArray> graph)
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