Class Solution
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public final class Solution1971 - Find if Path Exists in Graph.
Easy
There is a bi-directional graph with
nvertices, where each vertex is labeled from0ton - 1( inclusive ). The edges in the graph are represented as a 2D integer arrayedges, where each <code>edgesi = u<sub>i</sub>, v<sub>i</sub></code> denotes a bi-directional edge between vertex <code>u<sub>i</sub></code> and vertex <code>v<sub>i</sub></code>. Every vertex pair is connected by at most one edge, and no vertex has an edge to itself.You want to determine if there is a valid path that exists from vertex
sourceto vertexdestination.Given
edgesand the integersn,source, anddestination, returntrueif there is a valid path fromsourcetodestination, orfalseotherwise_._Example 1:
Input: n = 3, edges = \[\[0,1],1,2,2,0], source = 0, destination = 2
Output: true
Explanation: There are two paths from vertex 0 to vertex 2: - 0 → 1 → 2 - 0 → 2
Example 2:
Input: n = 6, edges = \[\[0,1],0,2,3,5,5,4,4,3], source = 0, destination = 5
Output: false
Explanation: There is no path from vertex 0 to vertex 5.
Constraints:
<code>1 <= n <= 2 * 10<sup>5</sup></code>
<code>0 <= edges.length <= 2 * 10<sup>5</sup></code>
edges[i].length == 2<code>0 <= u<sub>i</sub>, v<sub>i</sub><= n - 1</code>
<code>u<sub>i</sub> != v<sub>i</sub></code>
0 <= source, destination <= n - 1There are no duplicate edges.
There are no self edges.
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Constructor Summary
Constructors Constructor Description Solution()
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