Class Solution
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public final class Solution2864 - Maximum Odd Binary Number.
Easy
You are given a binary string
sthat contains at least one'1'.You have to rearrange the bits in such a way that the resulting binary number is the maximum odd binary number that can be created from this combination.
Return a string representing the maximum odd binary number that can be created from the given combination.
Note that the resulting string can have leading zeros.
Example 1:
Input: s = "010"
Output: "001"
Explanation: Because there is just one '1', it must be in the last position. So the answer is "001".
Example 2:
Input: s = "0101"
Output: "1001"
Explanation: One of the '1's must be in the last position. The maximum number that can be made with the remaining digits is "100". So the answer is "1001".
Constraints:
1 <= s.length <= 100sconsists only of'0'and'1'.scontains at least one'1'.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final StringmaximumOddBinaryNumber(String s)-
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Method Detail
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maximumOddBinaryNumber
final String maximumOddBinaryNumber(String s)
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