Class Solution
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public final class Solution899 - Orderly Queue.
Hard
You are given a string
sand an integerk. You can choose one of the firstkletters ofsand append it at the end of the string..Return the lexicographically smallest string you could have after applying the mentioned step any number of moves.
Example 1:
Input: s = "cba", k = 1
Output: "acb"
Explanation:
In the first move, we move the 1<sup>st</sup> character 'c' to the end, obtaining the string "bac".
In the second move, we move the 1<sup>st</sup> character 'b' to the end, obtaining the final result "acb".
Example 2:
Input: s = "baaca", k = 3
Output: "aaabc"
Explanation:
In the first move, we move the 1<sup>st</sup> character 'b' to the end, obtaining the string "aacab".
In the second move, we move the 3<sup>rd</sup> character 'c' to the end, obtaining the final result "aaabc".
Constraints:
1 <= k <= s.length <= 1000sconsist of lowercase English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final StringorderlyQueue(String s, Integer k)-
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Method Detail
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orderlyQueue
final String orderlyQueue(String s, Integer k)
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