1844 - Replace All Digits with Characters.

Easy

You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices.

There is a function shift(c, x), where c is a character and x is a digit, that returns the <code>x^th</code> character after c.

• For example, shift('a', 5) = 'f' and shift('x', 0) = 'x'.

For every odd index i, you want to replace the digit s[i] with shift(s[i-1], s[i]).

Return s after replacing all digits. It is guaranteed that shift(s[i-1], s[i]) will never exceed 'z'.

Example 1:

Input: s = "a1c1e1"

Output: "abcdef"

Explanation: The digits are replaced as follows:

• s1 -> shift('a',1) = 'b'

• s3 -> shift('c',1) = 'd'

• s5 -> shift('e',1) = 'f'

Example 2:

Input: s = "a1b2c3d4e"

Output: "abbdcfdhe"

Explanation: The digits are replaced as follows:

• s1 -> shift('a',1) = 'b'

• s3 -> shift('b',2) = 'd'

• s5 -> shift('c',3) = 'f'

• s7 -> shift('d',4) = 'h'

Constraints:

• 1 <= s.length <= 100

• s consists only of lowercase English letters and digits.

• shift(s[i-1], s[i]) <= 'z' for all odd indices i.