2670 - Find the Distinct Difference Array.

Easy

You are given a 0-indexed array nums of length n.

The distinct difference array of nums is an array diff of length n such that diff[i] is equal to the number of distinct elements in the suffix nums[i + 1, ..., n - 1] subtracted from the number of distinct elements in the prefix nums[0, ..., i].

Return the distinct difference array of nums.

Note that nums[i, ..., j] denotes the subarray of nums starting at index i and ending at index j inclusive. Particularly, if i > j then nums[i, ..., j] denotes an empty subarray.

Example 1:

Input: nums = 1,2,3,4,5

Output: -3,-1,1,3,5

Explanation:

For index i = 0, there is 1 element in the prefix and 4 distinct elements in the suffix. Thus, diff0 = 1 - 4 = -3.

For index i = 1, there are 2 distinct elements in the prefix and 3 distinct elements in the suffix. Thus, diff1 = 2 - 3 = -1.

For index i = 2, there are 3 distinct elements in the prefix and 2 distinct elements in the suffix. Thus, diff2 = 3 - 2 = 1.

For index i = 3, there are 4 distinct elements in the prefix and 1 distinct element in the suffix. Thus, diff3 = 4 - 1 = 3.

For index i = 4, there are 5 distinct elements in the prefix and no elements in the suffix. Thus, diff4 = 5 - 0 = 5.

Example 2:

Input: nums = 3,2,3,4,2

Output: -2,-1,0,2,3

Explanation:

For index i = 0, there is 1 element in the prefix and 3 distinct elements in the suffix. Thus, diff0 = 1 - 3 = -2.

For index i = 1, there are 2 distinct elements in the prefix and 3 distinct elements in the suffix. Thus, diff1 = 2 - 3 = -1.

For index i = 2, there are 2 distinct elements in the prefix and 2 distinct elements in the suffix. Thus, diff2 = 2 - 2 = 0.

For index i = 3, there are 3 distinct elements in the prefix and 1 distinct element in the suffix. Thus, diff3 = 3 - 1 = 2.

For index i = 4, there are 3 distinct elements in the prefix and no elements in the suffix. Thus, diff4 = 3 - 0 = 3.

Constraints:

• 1 <= n == nums.length <= 50

• 1 <= nums[i] <= 50