Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    3669 - Balanced K-Factor Decomposition.

    Medium

    Given two integers n and k, split the number n into exactly k positive integers such that the product of these integers is equal to n.

    Return any one split in which the maximum difference between any two numbers is minimized. You may return the result in any order.

    Example 1:

    Input: n = 100, k = 2

    Output: 10,10

    Explanation:

    The split [10, 10] yields 10 * 10 = 100 and a max-min difference of 0, which is minimal.

    Example 2:

    Input: n = 44, k = 3

    Output: 2,2,11

    Explanation:

    • Split [1, 1, 44] yields a difference of 43

    • Split [1, 2, 22] yields a difference of 21

    • Split [1, 4, 11] yields a difference of 10

    • Split [2, 2, 11] yields a difference of 9

    Therefore, [2, 2, 11] is the optimal split with the smallest difference 9.

    Constraints:

    • <code>4 <= n <= 10<sup>5</sup></code>

    • 2 &lt;= k &lt;= 5

    • k is strictly less than the total number of positive divisors of n.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final IntArray minDifference(Integer n, Integer k)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait