Class Solution
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public final class Solution3548 - Equal Sum Grid Partition II.
Hard
You are given an
m x nmatrixgridof positive integers. Your task is to determine if it is possible to make either one horizontal or one vertical cut on the grid such that:Each of the two resulting sections formed by the cut is non-empty.
The sum of elements in both sections is equal , or can be made equal by discounting at most one single cell in total (from either section).
If a cell is discounted, the rest of the section must remain connected.
Return
trueif such a partition exists; otherwise, returnfalse.Note: A section is connected if every cell in it can be reached from any other cell by moving up, down, left, or right through other cells in the section.
Example 1:
Input: grid = [1,4,2,3]
Output: true
Explanation:
A horizontal cut after the first row gives sums
1 + 4 = 5and2 + 3 = 5, which are equal. Thus, the answer istrue.
Example 2:
Input: grid = [1,2,3,4]
Output: true
Explanation:
A vertical cut after the first column gives sums
1 + 3 = 4and2 + 4 = 6.By discounting 2 from the right section (
6 - 2 = 4), both sections have equal sums and remain connected. Thus, the answer istrue.
Example 3:
Input: grid = [1,2,4,2,3,5]
Output: false
Explanation:
A horizontal cut after the first row gives
1 + 2 + 4 = 7and2 + 3 + 5 = 10.By discounting 3 from the bottom section (
10 - 3 = 7), both sections have equal sums, but they do not remain connected as it splits the bottom section into two parts ([2]and[5]). Thus, the answer isfalse.
Example 4:
Input: grid = [4,1,8,3,2,6]
Output: false
Explanation:
No valid cut exists, so the answer is
false.Constraints:
<code>1 <= m == grid.length <= 10<sup>5</sup></code>
<code>1 <= n == gridi.length <= 10<sup>5</sup></code>
<code>2 <= m * n <= 10<sup>5</sup></code>
<code>1 <= gridj<= 10<sup>5</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final BooleancanPartitionGrid(Array<IntArray> grid)-
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Method Detail
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canPartitionGrid
final Boolean canPartitionGrid(Array<IntArray> grid)
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