Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    3701 - Compute Alternating Sum.

    Easy

    You are given an integer array nums.

    The alternating sum of nums is the value obtained by adding elements at even indices and subtracting elements at odd indices. That is, nums[0] - nums[1] + nums[2] - nums[3]...

    Return an integer denoting the alternating sum of nums.

    Example 1:

    Input: nums = 1,3,5,7

    Output: \-4

    Explanation:

    • Elements at even indices are nums[0] = 1 and nums[2] = 5 because 0 and 2 are even numbers.

    • Elements at odd indices are nums[1] = 3 and nums[3] = 7 because 1 and 3 are odd numbers.

    • The alternating sum is nums[0] - nums[1] + nums[2] - nums[3] = 1 - 3 + 5 - 7 = -4.

    Example 2:

    Input: nums = 100

    Output: 100

    Explanation:

    • The only element at even indices is nums[0] = 100 because 0 is an even number.

    • There are no elements on odd indices.

    • The alternating sum is nums[0] = 100.

    Constraints:

    • 1 <= nums.length <= 100

    • 1 <= nums[i] <= 100

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer alternatingSum(IntArray nums)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait