Package it.unimi.dsi.fastutil.ints

Interface IntBinaryOperator

All Superinterfaces:
java.util.function.BiFunction<java.lang.Integer,​java.lang.Integer,​java.lang.Integer>, java.util.function.BinaryOperator<java.lang.Integer>, java.util.function.IntBinaryOperator
Functional Interface:
This is a functional interface and can therefore be used as the assignment target for a lambda expression or method reference.
@FunctionalInterface
public interface IntBinaryOperator
extends java.util.function.BinaryOperator<java.lang.Integer>, java.util.function.IntBinaryOperator
A type-specific BinaryOperator; provides methods operating both on objects and on primitives.
Since:
8.5.0
See Also:
BinaryOperator

  • Method Summary

    Modifier and Type Method Description
    int apply​(int x, int y)
    Computes the operator on the given inputs.
    default java.lang.Integer apply​(java.lang.Integer x, java.lang.Integer y)
    Deprecated.
    Please use the corresponding type-specific method instead.
    default int applyAsInt​(int x, int y)
    Deprecated.
    Please use apply(int, int).

    Methods inherited from interface java.util.function.BiFunction

    andThen

  • Method Details

    • apply

      int apply​(int x, int y)
      Computes the operator on the given inputs.
      Parameters:
      x - the first input.
      y - the second input.
      Returns:
      the output of the operator on the given inputs.

    • applyAsInt

      @Deprecated default int applyAsInt​(int x, int y)
      Deprecated.
      Please use apply(int, int).
      Specified by:
      applyAsInt in interface java.util.function.IntBinaryOperator
      Implementation Specification:
      This default implementation delegates to apply(int, int).

    • apply

      @Deprecated default java.lang.Integer apply​(java.lang.Integer x, java.lang.Integer y)
      Deprecated.
      Please use the corresponding type-specific method instead.
      Specified by:
      apply in interface java.util.function.BiFunction<java.lang.Integer,​java.lang.Integer,​java.lang.Integer>