Class IntElementaryModMath

java.lang.Object
org.apfloat.internal.IntElementaryModMath
Direct Known Subclasses:
IntModMath

public class IntElementaryModMath extends Object
Elementary modulo arithmetic functions for int data.

Modular addition and subtraction are trivial, when the modulus is less than 231 and overflow can be detected easily.

Modular multiplication is more complicated, and since it is usually the single most time consuming operation in the whole program execution, the very core of the Number Theoretic Transform (NTT), it should be carefully optimized.

The obvious (but not very efficient) algorithm for multiplying two ints and taking the remainder is

(int) ((long) a * b % modulus)

The first observation is that since the modulus is practically constant, it should be more efficient to calculate (once) the inverse of the modulus, and then subsequently multiply by the inverse modulus instead of dividing by the modulus.

The second observation is that to get the remainder of the division, we don't necessarily need the actual result of the division (we just want the remainder). So, we should discard the topmost 32 bits of the full 64-bit result whenever possible, to save a few operations.

The basic approach is to get some approximation of a * b / modulus. The approximation should be within +1 or -1 of the correct result. Then calculate a * b - approximateDivision * modulus to get the remainder. This calculation needs to use only the lowest 32 bits. As the modulus is less than 231 it is easy to detect the case when the approximate division was off by one (and the remainder is ±modulus off).

There are different algorithms to calculate the approximate division a * b / modulus. This implementation simply converts all the operands to double and performs the multiplications. This requires that converting between integer types and floating point types is efficient. On some platforms this may not be true; in that case it can be more efficient to perform the multiplications using 64-bit integer arithmetic.

To simplify the operations, we calculate the inverse modulus as 1.0 / (modulus + 0.5). Since the modulus is assumed to be prime, and a double has more bits for precision than an int, the approximate result of a * b / modulus will always be either correct or one too small (but never one too big).

Version:
1.0.2
Author:
Mikko Tommila
  • Constructor Details

    • IntElementaryModMath

      public IntElementaryModMath()
      Default constructor.
  • Method Details

    • modMultiply

      public final int modMultiply(int a, int b)
      Modular multiplication.
      Parameters:
      a - First operand.
      b - Second operand.
      Returns:
      a * b % modulus
    • modAdd

      public final int modAdd(int a, int b)
      Modular addition.
      Parameters:
      a - First operand.
      b - Second operand.
      Returns:
      (a + b) % modulus
    • modSubtract

      public final int modSubtract(int a, int b)
      Modular subtraction. The result is always >= 0.
      Parameters:
      a - First operand.
      b - Second operand.
      Returns:
      (a - b + modulus) % modulus
    • getModulus

      public final int getModulus()
      Get the modulus.
      Returns:
      The modulus.
    • setModulus

      public final void setModulus(int modulus)
      Set the modulus.
      Parameters:
      modulus - The modulus.