g0801_0900.s0844_backspace_string_compare

Class Solution

java.lang.Object

g0801_0900.s0844_backspace_string_compare.Solution

public class Solution
extends Object

844 - Backspace String Compare.

Easy

Given two strings s and t, return true if they are equal when both are typed into empty text editors. '#' means a backspace character.

Note that after backspacing an empty text, the text will continue empty.

Example 1:

Input: s = “ab#c”, t = “ad#c”

Output: true

Explanation: Both s and t become “ac”.

Example 2:

Input: s = “ab##”, t = “c#d#”

Output: true

Explanation: Both s and t become "".

Example 3:

Input: s = “a#c”, t = “b”

Output: false

Explanation: s becomes “c” while t becomes “b”.

Constraints:

• 1 <= s.length, t.length <= 200
• s and t only contain lowercase letters and '#' characters.

Follow up: Can you solve it in O(n) time and O(1) space?

Constructor Summary

Constructors

Constructor and Description
Solution()

Method Summary

Modifier and Type	Method and Description
boolean	backspaceCompare(String s, String t)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail

Solution

public Solution()

Method Detail

backspaceCompare

public boolean backspaceCompare(String s,
                                String t)