public class Solution extends Object
2169 - Count Operations to Obtain Zero.
Easy
You are given two non-negative integers num1
and num2
.
In one operation , if num1 >= num2
, you must subtract num2
from num1
, otherwise subtract num1
from num2
.
num1 = 5
and num2 = 4
, subtract num2
from num1
, thus obtaining num1 = 1
and num2 = 4
. However, if num1 = 4
and num2 = 5
, after one operation, num1 = 4
and num2 = 1
.Return the number of operations required to make either num1 = 0
or num2 = 0
.
Example 1:
Input: num1 = 2, num2 = 3
Output: 3
Explanation:
Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.
Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1.
Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.
Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.
So the total number of operations required is 3.
Example 2:
Input: num1 = 10, num2 = 10
Output: 1
Explanation:
Now num1 = 0 and num2 = 10. Since num1 == 0, we are done.
So the total number of operations required is 1.
Constraints:
0 <= num1, num2 <= 105
Constructor and Description |
---|
Solution() |
Modifier and Type | Method and Description |
---|---|
int |
countOperations(int num1,
int num2) |
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