public class Solution extends Object
787 - Cheapest Flights Within K Stops.
Medium
There are n
cities connected by some number of flights. You are given an array flights
where flights[i] = [fromi, toi, pricei]
indicates that there is a flight from city fromi
to city toi
with cost pricei
.
You are also given three integers src
, dst
, and k
, return the cheapest price from src
to dst
with at most k
stops. If there is no such route, return -1
.
Example 1:
Input: n = 3, flights = [[0,1,100],[1,2,100],[0,2,500]], src = 0, dst = 2, k = 1
Output: 200
Explanation:
The graph is shown.
The cheapest price from city 0
to city 2
with at most 1 stop costs 200, as marked red in the picture.
Example 2:
Input: n = 3, flights = [[0,1,100],[1,2,100],[0,2,500]], src = 0, dst = 2, k = 0
Output: 500
Explanation:
The graph is shown.
The cheapest price from city 0
to city 2
with at most 0 stop costs 500, as marked blue in the picture.
Constraints:
1 <= n <= 100
0 <= flights.length <= (n * (n - 1) / 2)
flights[i].length == 3
0 <= fromi, toi < n
fromi != toi
1 <= pricei <= 104
0 <= src, dst, k < n
src != dst
Constructor and Description |
---|
Solution() |
Modifier and Type | Method and Description |
---|---|
int |
findCheapestPrice(int n,
int[][] flights,
int src,
int dst,
int k) |
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