public class Solution extends Object
834 - Sum of Distances in Tree.
Hard
There is an undirected connected tree with n nodes labeled from 0 to n - 1 and n - 1 edges.
You are given the integer n and the array edges where edges[i] = [ai, bi] indicates that there is an edge between nodes ai and bi in the tree.
Return an array answer of length n where answer[i] is the sum of the distances between the ith node in the tree and all other nodes.
Example 1:

Input: n = 6, edges = [[0,1],[0,2],[2,3],[2,4],[2,5]]
Output: [8,12,6,10,10,10]
Explanation: The tree is shown above.
We can see that dist(0,1) + dist(0,2) + dist(0,3) + dist(0,4) + dist(0,5) equals 1 + 1 + 2 + 2 + 2 = 8.
Hence, answer[0] = 8, and so on.
Example 2:

Input: n = 1, edges = []
Output: [0]
Example 3:

Input: n = 2, edges = [[1,0]]
Output: [1,1]
Constraints:
1 <= n <= 3 * 104edges.length == n - 1edges[i].length == 20 <= ai, bi < nai != bi| Constructor and Description |
|---|
Solution() |
| Modifier and Type | Method and Description |
|---|---|
int[] |
sumOfDistancesInTree(int n,
int[][] edges) |
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