public class Solution extends Object
2012 - Sum of Beauty in the Array.
Medium
You are given a 0-indexed integer array nums. For each index i (1 <= i <= nums.length - 2) the beauty of nums[i] equals:
2, if nums[j] < nums[i] < nums[k], for all 0 <= j < i and for all i < k <= nums.length - 1.1, if nums[i - 1] < nums[i] < nums[i + 1], and the previous condition is not satisfied.0, if none of the previous conditions holds.Return the sum of beauty of all nums[i] where 1 <= i <= nums.length - 2.
Example 1:
Input: nums = [1,2,3]
Output: 2
Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 2.
Example 2:
Input: nums = [2,4,6,4]
Output: 1
Explanation: For each index i in the range 1 <= i <= 2:
The beauty of nums[1] equals 1.
The beauty of nums[2] equals 0.
Example 3:
Input: nums = [3,2,1]
Output: 0
Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 0.
Constraints:
3 <= nums.length <= 1051 <= nums[i] <= 105| Constructor and Description |
|---|
Solution() |
| Modifier and Type | Method and Description |
|---|---|
int |
sumOfBeauties(int[] nums) |
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