public class Solution extends Object
2460 - Apply Operations to an Array.
Easy
You are given a 0-indexed array nums of size n consisting of non-negative integers.
You need to apply n - 1 operations to this array where, in the ith operation ( 0-indexed ), you will apply the following on the ith element of nums:
nums[i] == nums[i + 1], then multiply nums[i] by 2 and set nums[i + 1] to 0. Otherwise, you skip this operation.After performing all the operations, shift all the 0’s to the end of the array.
[1,0,2,0,0,1] after shifting all its 0’s to the end, is [1,2,1,0,0,0].Return the resulting array.
Note that the operations are applied sequentially , not all at once.
Example 1:
Input: nums = [1,2,2,1,1,0]
Output: [1,4,2,0,0,0]
Explanation: We do the following operations:
i = 0: nums[0] and nums[1] are not equal, so we skip this operation.
i = 1: nums[1] and nums[2] are equal, we multiply nums[1] by 2 and change nums[2] to 0. The array becomes [1, 4 , 0 ,1,1,0].
i = 2: nums[2] and nums[3] are not equal, so we skip this operation.
i = 3: nums[3] and nums[4] are equal, we multiply nums[3] by 2 and change nums[4] to 0. The array becomes [1,4,0, 2 , 0 ,0].
i = 4: nums[4] and nums[5] are equal, we multiply nums[4] by 2 and change nums[5] to 0. The array becomes [1,4,0,2, 0 , 0 ].
After that, we shift the 0’s to the end, which gives the array [1,4,2,0,0,0].
Example 2:
Input: nums = [0,1]
Output: [1,0]
Explanation: No operation can be applied, we just shift the 0 to the end.
Constraints:
2 <= nums.length <= 20000 <= nums[i] <= 1000| Constructor and Description |
|---|
Solution() |
| Modifier and Type | Method and Description |
|---|---|
int[] |
applyOperations(int[] nums) |
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