public class Solution extends Object
1640 - Check Array Formation Through Concatenation.
Easy
You are given an array of distinct integers arr
and an array of integer arrays pieces
, where the integers in pieces
are distinct. Your goal is to form arr
by concatenating the arrays in pieces
in any order. However, you are not allowed to reorder the integers in each array pieces[i]
.
Return true
if it is possible to form the array arr
from pieces
. Otherwise, return false
.
Example 1:
Input: arr = [15,88], pieces = [[88],[15]]
Output: true
Explanation: Concatenate [15] then [88]
Example 2:
Input: arr = [49,18,16], pieces = [[16,18,49]]
Output: false
Explanation: Even though the numbers match, we cannot reorder pieces[0].
Example 3:
Input: arr = [91,4,64,78], pieces = [[78],[4,64],[91]]
Output: true
Explanation: Concatenate [91] then [4,64] then [78]
Constraints:
1 <= pieces.length <= arr.length <= 100
sum(pieces[i].length) == arr.length
1 <= pieces[i].length <= arr.length
1 <= arr[i], pieces[i][j] <= 100
arr
are distinct.pieces
are distinct (i.e., If we flatten pieces in a 1D array, all the integers in this array are distinct).Constructor and Description |
---|
Solution() |
Modifier and Type | Method and Description |
---|---|
boolean |
canFormArray(int[] arr,
int[][] pieces) |
Copyright © 2023. All rights reserved.