public class Solution extends Object
435 - Non-overlapping Intervals.
Medium
Given an array of intervals intervals
where intervals[i] = [starti, endi]
, return the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping.
Example 1:
Input: intervals = 1,2],[2,3],[3,4],[1,3
Output: 1
Explanation: [1,3] can be removed and the rest of the intervals are non-overlapping.
Example 2:
Input: intervals = 1,2],[1,2],[1,2
Output: 2
Explanation: You need to remove two [1,2] to make the rest of the intervals non-overlapping.
Example 3:
Input: intervals = 1,2],[2,3
Output: 0
Explanation: You don’t need to remove any of the intervals since they’re already non-overlapping.
Constraints:
1 <= intervals.length <= 105
intervals[i].length == 2
-5 * 104 <= starti < endi <= 5 * 104
Constructor and Description |
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Solution() |
Modifier and Type | Method and Description |
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int |
eraseOverlapIntervals(int[][] intervals)
This is sorting my starting time, the key here is that we’ll want to update end time when an erasure is needed: we use the smaller end time instead of the bigger one which is more likely to overlap with others.
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