public class Solution extends Object
994 - Rotting Oranges.
Medium
You are given an m x n grid where each cell can have one of three values:
0 representing an empty cell,1 representing a fresh orange, or2 representing a rotten orange.Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.
Return the minimum number of minutes that must elapse until no cell has a fresh orange. If this is impossible, return -1.
Example 1:

Input: grid = 2,1,1],[1,1,0],[0,1,1
Output: 4
Example 2:
Input: grid = 2,1,1],[0,1,1],[1,0,1
Output: -1
Explanation: The orange in the bottom left corner (row 2, column 0) is never rotten, because rotting only happens 4-directionally.
Example 3:
Input: grid = 0,2
Output: 0
Explanation: Since there are already no fresh oranges at minute 0, the answer is just 0.
Constraints:
m == grid.lengthn == grid[i].length1 <= m, n <= 10grid[i][j] is 0, 1, or 2.| Constructor and Description |
|---|
Solution() |
| Modifier and Type | Method and Description |
|---|---|
int |
orangesRotting(int[][] grid) |
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