public class Solution extends Object
832 - Flipping an Image.
Easy
Given an n x n
binary matrix image
, flip the image horizontally, then invert it, and return the resulting image.
To flip an image horizontally means that each row of the image is reversed.
[1,1,0]
horizontally results in [0,1,1]
.To invert an image means that each 0
is replaced by 1
, and each 1
is replaced by 0
.
[0,1,1]
results in [1,0,0]
.Example 1:
Input: image = 1,1,0],[1,0,1],[0,0,0
Output: 1,0,0],[0,1,0],[1,1,1
Explanation:
First reverse each row: 0,1,1],[1,0,1],[0,0,0.
Then, invert the image: 1,0,0],[0,1,0],[1,1,1
Example 2:
Input: image = 1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0
Output: 1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0
Explanation:
First reverse each row: 0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1.
Then invert the image: 1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0
Constraints:
n == image.length
n == image[i].length
1 <= n <= 20
images[i][j]
is either 0
or 1
.Constructor and Description |
---|
Solution() |
Modifier and Type | Method and Description |
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int[][] |
flipAndInvertImage(int[][] image) |
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