Directory

If optional depth argument is not given, will recurse until it runs out of contents.

An iterator over the contents of this directory.

If this path is a directory, recursively iterate over its contents. The supplied condition is a filter which is applied to each element, with that branch of the tree being closed off if it is false. So for example if the condition is false for some subdirectory, nothing under that directory will be in the Iterator. If it's true, all files for which the condition holds and are directly in that subdirectory are in the Iterator, and all sub-subdirectories are recursively evaluated

Creates a new Path with the specified path appended. Assumes the type of the new component implies the type of the result.

Deletes the path recursively. Returns false on failure. Use with caution!

Compares the receiver object (this) with the argument object (that) for equivalence.

Any implementation of this method should be an equivalence relation:

• It is reflexive: for any instance x of type Any, x.equals(x) should return true.
• It is symmetric: for any instances x and y of type Any, x.equals(y) should return true if and only if y.equals(x) returns true.
• It is transitive: for any instances x, y, and z of type Any if x.equals(y) returns true and y.equals(z) returns true, then x.equals(z) should return true.

If you override this method, you should verify that your implementation remains an equivalence relation. Additionally, when overriding this method it is usually necessary to override hashCode to ensure that objects which are "equal" (o1.equals(o2) returns true) hash to the same scala.Int. (o1.hashCode.equals(o2.hashCode)).

Calculate a hash code value for the object.

The default hashing algorithm is platform dependent.

Note that it is allowed for two objects to have identical hash codes (o1.hashCode.equals(o2.hashCode)) yet not be equal (o1.equals(o2) returns false). A degenerate implementation could always return 0. However, it is required that if two objects are equal (o1.equals(o2) returns true) that they have identical hash codes (o1.hashCode.equals(o2.hashCode)). Therefore, when overriding this method, be sure to verify that the behavior is consistent with the equals method.

If this path is absolute, returns it: otherwise, returns an absolute path made up of root / this.

Returns a string representation of the object.

The default representation is platform dependent.

Equivalent to walkFilter(_ => true).