Tuple15FromExpr

given Tuple15FromExpr[T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15](using val x$1: Type[T1], val x$2: Type[T2], val x$3: Type[T3], val x$4: Type[T4], val x$5: Type[T5], val x$6: Type[T6], val x$7: Type[T7], val x$8: Type[T8], val x$9: Type[T9], val x$10: Type[T10], val x$11: Type[T11], val x$12: Type[T12], val x$13: Type[T13], val x$14: Type[T14], val x$15: Type[T15], val x$16: FromExpr[T1], val x$17: FromExpr[T2], val x$18: FromExpr[T3], val x$19: FromExpr[T4], val x$20: FromExpr[T5], val x$21: FromExpr[T6], val x$22: FromExpr[T7], val x$23: FromExpr[T8], val x$24: FromExpr[T9], val x$25: FromExpr[T10], val x$26: FromExpr[T11], val x$27: FromExpr[T12], val x$28: FromExpr[T13], val x$29: FromExpr[T14], val x$30: FromExpr[T15]): FromExpr[(T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15)]

Default implementation of FromExpr[Tuple15[...]]

  • Transform '{Tuple5(x1, ..., x15)} into Some(Tuple5(x1, ..., x15)) if all xi can be transformed using FromExpr[Ti]
  • Otherwise returns None

Value members

Concrete methods

def unapply(x: Expr[(T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15)])(using Quotes): Option[(T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15)]

Concrete fields

protected
val x$1: Type[T1]
protected
val x$10: Type[T10]
protected
val x$11: Type[T11]
protected
val x$12: Type[T12]
protected
val x$13: Type[T13]
protected
val x$14: Type[T14]
protected
val x$15: Type[T15]
protected
protected
protected
protected
protected
val x$2: Type[T2]
protected
protected
protected
protected
protected
protected
protected
protected
protected
protected
protected
val x$3: Type[T3]
protected
protected
val x$4: Type[T4]
protected
val x$5: Type[T5]
protected
val x$6: Type[T6]
protected
val x$7: Type[T7]
protected
val x$8: Type[T8]
protected
val x$9: Type[T9]