Package no.digipost.tuple

Interface Hextuple<T1,T2,T3,T4,T5,T6>

Type Parameters:

T1 - The type of the first value

T2 - The type of the second value

T3 - The type of the third value

T4 - The type of the fourth value

T5 - The type of the fifth value

T6 - The type of the sixth value

All Superinterfaces:

ViewableAsHextuple<T1,T2,T3,T4,T5,T6>

public interface Hextuple<T1,T2,T3,T4,T5,T6>
extends ViewableAsHextuple<T1,T2,T3,T4,T5,T6>

A hextuple is a simple composition of six arbitrary values (objects). A hextuple captures no semantics of the six values, and they are only referred to as "the first", "the second", "the third", "the fourth", "the fifth", and "the sixth" value.

Method Summary

Modifier and Type	Method	Description
Hextuple<T1,T2,T3,T4,T5,T6>	asHextuple()
T5	fifth()
T1	first()
static <T1,T2,T3,T4,T5,T6> Hextuple<T1,T2,T3,T4,T5,T6>	flatten(Tuple<Tuple<Tuple<Tuple<Tuple<T1,T2>,T3>,T4>,T5>,T6> nestedTuple)
T4	fourth()
<S1,S2,S3,S4,S5,S6> Hextuple<S1,S2,S3,S4,S5,S6>	map(Function<? super T1,? extends S1> firstMapper, Function<? super T2,? extends S2> secondMapper, Function<? super T3,? extends S3> thirdMapper, Function<? super T4,? extends S4> fourthMapper, Function<? super T5,? extends S5> fifthMapper, Function<? super T6,? extends S6> sixthMapper)	Create a new hextuple by applying a function to each element, and putting the results into a new hextuple.
<S5> Hextuple<T1,T2,T3,T4,S5,T6>	mapFifth(Function<? super T5,? extends S5> mapper)	Create a new hextuple by applying a function to the fifth element, and putting the result as the fifth element of the new hextuple.
<S1> Hextuple<S1,T2,T3,T4,T5,T6>	mapFirst(Function<? super T1,? extends S1> mapper)	Create a new hextuple by applying a function to the first element, and putting the result as the first element of the new hextuple.
<S4> Hextuple<T1,T2,T3,S4,T5,T6>	mapFourth(Function<? super T4,? extends S4> mapper)	Create a new hextuple by applying a function to the fourth element, and putting the result as the fourth element of the new hextuple.
<S2> Hextuple<T1,S2,T3,T4,T5,T6>	mapSecond(Function<? super T2,? extends S2> mapper)	Create a new hextuple by applying a function to the second element, and putting the result as the second element of the new hextuple.
<S6> Hextuple<T1,T2,T3,T4,T5,S6>	mapSixth(Function<? super T6,? extends S6> mapper)	Create a new hextuple by applying a function to the sixth element, and putting the result as the sixth element of the new hextuple.
<S3> Hextuple<T1,T2,S3,T4,T5,T6>	mapThird(Function<? super T3,? extends S3> mapper)	Create a new hextuple by applying a function to the third element, and putting the result as the third element of the new hextuple.
static <T1,T2,T3,T4,T5,T6> Hextuple<T1,T2,T3,T4,T5,T6>	of(T1 first, T2 second, T3 third, T4 fourth, T5 fifth, T6 sixth)
T2	second()
T6	sixth()
T3	third()
<R> R	to(HexaFunction<? super T1,? super T2,? super T3,? super T4,? super T5,? super T6,R> convertor)	Convert this hextuple to an instance of an arbitrary type.

Method Detail

of

static <T1,T2,T3,T4,T5,T6> Hextuple<T1,T2,T3,T4,T5,T6> of(T1 first,
                                                                                                                      T2 second,
                                                                                                                      T3 third,
                                                                                                                      T4 fourth,
                                                                                                                      T5 fifth,
                                                                                                                      T6 sixth)

flatten

static <T1,T2,T3,T4,T5,T6> Hextuple<T1,T2,T3,T4,T5,T6> flatten(Tuple<Tuple<Tuple<Tuple<Tuple<T1,T2>,T3>,T4>,T5>,T6> nestedTuple)

first

T1 first()

Returns:

the first value

second

T2 second()

Returns:

the second value

third

T3 third()

Returns:

the third value

fourth

T4 fourth()

Returns:

the fourth value

fifth

T5 fifth()

Returns:

the fifth value

sixth

T6 sixth()

Returns:

the sixth value

mapFirst

<S1> Hextuple<S1,T2,T3,T4,T5,T6> mapFirst(Function<? super T1,? extends S1> mapper)

Create a new hextuple by applying a function to the first element, and putting the result as the first element of the new hextuple.

Parameters:

mapper - the function to apply to the first element

Returns:

the new hextuple

mapSecond

<S2> Hextuple<T1,S2,T3,T4,T5,T6> mapSecond(Function<? super T2,? extends S2> mapper)

Create a new hextuple by applying a function to the second element, and putting the result as the second element of the new hextuple.

Parameters:

mapper - the function to apply to the second element

Returns:

the new hextuple

mapThird

<S3> Hextuple<T1,T2,S3,T4,T5,T6> mapThird(Function<? super T3,? extends S3> mapper)

Create a new hextuple by applying a function to the third element, and putting the result as the third element of the new hextuple.

Parameters:

mapper - the function to apply to the third element

Returns:

the new hextuple

mapFourth

<S4> Hextuple<T1,T2,T3,S4,T5,T6> mapFourth(Function<? super T4,? extends S4> mapper)

Create a new hextuple by applying a function to the fourth element, and putting the result as the fourth element of the new hextuple.

Parameters:

mapper - the function to apply to the fourth element

Returns:

the new hextuple

mapFifth

<S5> Hextuple<T1,T2,T3,T4,S5,T6> mapFifth(Function<? super T5,? extends S5> mapper)

Create a new hextuple by applying a function to the fifth element, and putting the result as the fifth element of the new hextuple.

Parameters:

mapper - the function to apply to the fifth element

Returns:

the new hextuple

mapSixth

<S6> Hextuple<T1,T2,T3,T4,T5,S6> mapSixth(Function<? super T6,? extends S6> mapper)

Create a new hextuple by applying a function to the sixth element, and putting the result as the sixth element of the new hextuple.

Parameters:

mapper - the function to apply to the sixth element

Returns:

the new hextuple

map

<S1,S2,S3,S4,S5,S6> Hextuple<S1,S2,S3,S4,S5,S6> map(Function<? super T1,? extends S1> firstMapper,
                                                                                                                Function<? super T2,? extends S2> secondMapper,
                                                                                                                Function<? super T3,? extends S3> thirdMapper,
                                                                                                                Function<? super T4,? extends S4> fourthMapper,
                                                                                                                Function<? super T5,? extends S5> fifthMapper,
                                                                                                                Function<? super T6,? extends S6> sixthMapper)

Create a new hextuple by applying a function to each element, and putting the results into a new hextuple.

Parameters:

firstMapper - the function to apply to the first element

secondMapper - the function to apply to the second element

thirdMapper - the function to apply to the third element

fourthMapper - the function to apply to the fourth element

fifthMapper - the function to apply to the fifth element

sixthMapper - the function to apply to the sixth element

Returns:

the new hextuple

asHextuple

Hextuple<T1,T2,T3,T4,T5,T6> asHextuple()

Specified by:

asHextuple in interface ViewableAsHextuple<T1,T2,T3,T4,T5,T6>

Returns:

this hextuple instance

to

<R> R to(HexaFunction<? super T1,? super T2,? super T3,? super T4,? super T5,? super T6,R> convertor)

Convert this hextuple to an instance of an arbitrary type.

Type Parameters:

R - The type of the resulting instance

Parameters:

convertor - the function used to convert the contained values to a resulting compound instance.

Returns:

the result from the given function